prove that cos4x=1-8sin xsquare cos square x solve it detail
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cos2×2x= 1-2sin^2(2x)
= 1-2×(2sinxcosx)^2
=1-8sin^2xcos^2x
= 1-2×(2sinxcosx)^2
=1-8sin^2xcos^2x
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cos4x=cos2(2x)
cos4x=1-2sin²2x
cos4x=1-2(sin2x)²
cos4x=1-2(2sinxcosx)²
cos4x=1-2(4sin²xcos²x)
cos4x=1-8sin²xcos²x
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