Prove that cos55°+cos65°+cos175°= 0
Answers
Answered by
1
Sum-to-product identity: .cosA+cosB=2⋅cos(A+B2)cos(A−B2)
We have: cos55o+cos65o+cos175o⏟
. . . . .=cos55o+⏞2⋅cos120ocos55o
. . . . .=cos55o+2(−12)cos55o
. . . . .=cos55o−cos55o
. . . . .=0
We have: cos55o+cos65o+cos175o⏟
. . . . .=cos55o+⏞2⋅cos120ocos55o
. . . . .=cos55o+2(−12)cos55o
. . . . .=cos55o−cos55o
. . . . .=0
Similar questions