Prove that Cos6A+Sin6A=1-3Sin2A*Cos2A
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Step-by-step explanation:
cos^6A+sin^6A
=(cos²A)³+(sin²A)³
=(cos²A+sin²A)(cos⁴A-sin²Acos²A+sin⁴A)
=cos⁴A+sin⁴A-sin²Acos²A
=(cos²A+sin²A)²-2sin²Acos²A-sin²cos²A
=1-3sin²Acos²A
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