Math, asked by rcjaiyogeshwar4222, 10 months ago

Prove that Cos6A+Sin6A=1-3Sin2A*Cos2A

Answers

Answered by sandy1816
4

Step-by-step explanation:

cos^6A+sin^6A

=(cos²A)³+(sin²A)³

=(cos²A+sin²A)(cos⁴A-sin²Acos²A+sin⁴A)

=cos⁴A+sin⁴A-sin²Acos²A

=(cos²A+sin²A)²-2sin²Acos²A-sin²cos²A

=1-3sin²Acos²A

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