Question

Prove that cos6x +cos4x / sin6x - sin 4x = cot x

Answer 1

Answer:

answer...................

Answer 2

$LHS = \frac{cos 6x + cos 4x }{sin 6x - sin 4x }$

$= \frac{\cancel {2 cos \Big( \frac{6x+4x}{2}\Big)} cos \Big(\frac{6x -4x}{2} \Big) }{\cancel {2 cos \Big( \frac{6x+4x}{2}\Big) }sin \Big(\frac{6x -4x}{2} \Big) }$

$= \frac{ cos \Big(\frac{2x}{2}\Big)}{sin \Big(\frac{2x}{2}\Big)}$

$= \frac{cos x }{sin x }$

$= cot x$

$= RHS$

Therefore.,

$\red{ \frac{cos 6x + cos 4x }{sin 6x - sin 4x }}$

$\green {= cot x}$

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