prove that cos9° + sin9°/
cos9° - sin9°
=cos36
Answers
Answered by
1
LHS = (Cos9° + Sin9°) / (Cos9° - Sin9°)
Divide by Nr and Dr by Cos9° ...
LHS = (1 + Tan9°) / (1 - Tan9°)
= (Tan 45° + Tan 9°) / (1 - Tan 45° * Tan 9°)
= Tan (45°+9°)
= Tan 54°
= Cot 36°.
Hope it helps
And thanks for asking doubt
Answered by
2
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