prove that cosA÷1+SinA+1+SinA÷cosA=2 SceA
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To Prove
cosA/(1 + sinA) + (1 + sinA)/cosA = 2 secA
L.H.S → cosA/(1 + sinA) + (1 + sinA)/cosA
→ [cos²A + (1 + sinA)²]/(1 + sinA)cosA
→ (cos²A + 1 + sin²A + 2 sinA)/cosA(1 + sinA)
→ (1 - sin²A + 1 + sin²A + 2sinA)/cosA(1 + sinA)
→ (2 + 2sinA)/cosA(1 + sinA)
→ 2(1 + sinA)/cosA(1 + sinA)
→ 2/cosA or 2 × 1/cosA
→ 2 secA = R.H.S
Hence Proved
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