prove that
cosA / 1 + sinA + 1 + sinA / cosA = 2 secA
Answers
Answered by
7
hey friend
Answer will be
LHS =cosA/(1+sinA) +(1+sinA)/cosA ={cos²A +(1+sinA)²}/cosA.(1+sinA)={cos²A+1+sin²A+2sinA}/cosA.(1+sinA)use sin²∅ +cos²∅ =1=(1+1+2sinA)/cosA(1+sinA)=2
Hope it helps
Answer will be
LHS =cosA/(1+sinA) +(1+sinA)/cosA ={cos²A +(1+sinA)²}/cosA.(1+sinA)={cos²A+1+sin²A+2sinA}/cosA.(1+sinA)use sin²∅ +cos²∅ =1=(1+1+2sinA)/cosA(1+sinA)=2
Hope it helps
yana83:
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