prove that cosA/1+sinA + 1+sinA/cosA =2secA
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Answered by
6
=[(1+sinA)(1+sinA) + cosA.cosA]/cosA(1+sinA)
=2(1+sinA)/cosA(1+sinA)
=2/cosA
=2secA
SOURCE : YAAHOO ANSWERS(https://in.answers.yahoo.com/question/index?qid=20090423024123AAZ178l)
=2(1+sinA)/cosA(1+sinA)
=2/cosA
=2secA
SOURCE : YAAHOO ANSWERS(https://in.answers.yahoo.com/question/index?qid=20090423024123AAZ178l)
syedairam:
can you explain me 2 line
Answered by
4
=[(1+sinA)(1+sinA) + cosA.cosA]/cosA(1+sinA)
=2(1+sinA)/cosA(1+sinA)
=2/cosA
=2secA
=2(1+sinA)/cosA(1+sinA)
=2/cosA
=2secA
hey where you went
this quetion you will be check in rd sharma or rs agrwaal
if that was the thing i would not ask here
from which state you
telangana
nd you
u.p
LHS =cosA/(1+sinA) +(1+ sinA)/cosA ={cos²A +(1+sinA)²}/cosA.(1+sinA) ={cos²A+1+sin²A+2sinA}/cosA.(1+sinA) use sin²∅ +cos²∅ =1 2sec²∅
thanks
i understood
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