Question

prove that cosA/1+sinA+1+sinA/cosA=2secA​

Answer 1

Answer:

[(1+sinA)(1+sinA)+(cosA] cos

A(1+sinA)= 2(1 sin A) / cos A (1+sinA)= 2/cos A =2sec A hence proud

Step-by-step explanation:

=

Answer 2

Answer: 2 sec A

Step-by-step explanation:

$cosA/(1+sinA)+(1+sinA)/cosA=2secA\\cosA(cosA)/1+sinA(cosA)+1+sinA(1+sinA)/cosA(1+sinA)\\cos^2A+1^2+2sinA+sin^2A/(cosA)(1+sinA)\\using,sin^A+cos^2A=1\\\\2+2sinA/cosA(1+sinA)\\2(1+sinA)/cosA(1+sinA)\\2/cosA\\2/1/secA\\=2secA$