Question

prove that cosA/1+sinA+ 1+sinA/cosA=2secA​

Answer 1

Answer:

Proved

Step-by-step explanation:

LHS =cosA/(1+sinA) +(1+sinA)/cosA  

={cos²A +(1+sinA)²}/cosA.(1+sinA)

={cos²A+1+sin²A+2sinA}/cosA.(1+sinA)

use sin²∅ +cos²∅ =1

=(1+1+2sinA)/cosA(1+sinA)

=2(1+sinA)/cosA(1+sinA)

=2/cosA

=2secA = RHS