prove that cosA / (1-sinA) + cosA /(1+sinA) = 2secA
Answers
Answered by
1
Answer:
Step-by-step explanation:
LHS
[cosA/(1-sinA)] + [cosA/(1+sinA)
Taking LCM
[cosA(1+sinA) + cosA(1-sinA)]/[(1-sinA)(1+sinA)]
=(cosA+cotA + cosA - cotA)/(1-sin²A)
=2cosA/cos²A
=2/cosA
=2secA
RHS
Answered by
1
Step-by-step explanation:
LHS
[cosA/(1-sinA)] + [cosA/(1+sinA)
Taking LCM
[cosA(1+sinA) + cosA(1-sinA)]/[(1-sinA)(1+sinA)]
=(cosA+cotA + cosA - cotA)/(1-sin²A)
=2cosA/cos²A
=2/cosA
=2secA
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