Math, asked by shreyags15, 10 months ago

prove that cosA / (1-sinA) + cosA /(1+sinA) = 2secA

Answers

Answered by pritamdash6365
1

Answer:

Step-by-step explanation:

LHS

[cosA/(1-sinA)] + [cosA/(1+sinA)

Taking LCM

[cosA(1+sinA) + cosA(1-sinA)]/[(1-sinA)(1+sinA)]

=(cosA+cotA + cosA - cotA)/(1-sin²A)

=2cosA/cos²A

=2/cosA

=2secA

RHS

Answered by pooja9147
1

Step-by-step explanation:

LHS

[cosA/(1-sinA)] + [cosA/(1+sinA)

Taking LCM

[cosA(1+sinA) + cosA(1-sinA)]/[(1-sinA)(1+sinA)]

=(cosA+cotA + cosA - cotA)/(1-sin²A)

=2cosA/cos²A

=2/cosA

=2secA

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