Prove that cosA/ (1-sinA) +cosA/ (1+sinA) =2secA
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cosA/(1-sinA)+cosA/(1+sinA)=LHS
cosA + cosA/(1-sinA)(1+sinA)
2cosA/1^2-sinA^2. [1^2-sinA^2=cos^2A]
2cosA/cos^2A
2×1/cosA. [1/cosA=secA]
2secA=RHS
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