Question

prove that: cosA/1-sinA=secA+tanA​

Answer 1

please check the answer....

Answer 2

$\frac{cosa}{1 - sina} \\ \\ = \frac{cosa(1 + sina)}{1 - {sin}^{2}a } \\ \\ = \frac{cosa(1 + sina)}{ {cosa}^{2}a } \\ \\ = \frac{1 + sina}{cosa} \\ \\ = seca + tana$