prove that : cosa/1-sina +sina/1-cosa+1= sina cosa/ (1-sina) (1-cosa)
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Step-by-step explanation:
cosA/1-sinA + sinA/1-cosA + 1 = sinAcosA/(1-sinA)(1-cosA)
LHS
= {cosA(1-cosA) + sinA(1-sinA) + (1-sinA)(1-cosA)}/(1-sinA)(1-cosA)
= (cosA - cos^2A + sinA - sin^2A + 1 - cosA - sinA + sinAcosA)/(1-sinA)(1-cosA)
= (-cos^2A - sin^2A + 1 + sinAcosA)/(1-sinA)(1-cosA)
= {-(cos^2A + sin^2A) + 1 + sinAcosA}/(1-sinA)(1-cosA)
= ( -1 + 1 + sinAcosA)/(1-sinA)(1-cosA)
= sinAcosA/(1-sinA)(1-cosA)
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