prove that (cosA)/(1+tanA)-(sinA)/(1+cotA)=cosA-sinA
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Answered by
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hey mate!
cosA/(cos +sinA)/cosA - sinA/(cosA+sinA)/sinA
= cos^2A - Sin^2A/ cosA + SinA
= (cosA - SinA) (cosA+SinA) / (cosA+sinA)
= CosA - SinA
hope it helps!
#JaiHind
cosA/(cos +sinA)/cosA - sinA/(cosA+sinA)/sinA
= cos^2A - Sin^2A/ cosA + SinA
= (cosA - SinA) (cosA+SinA) / (cosA+sinA)
= CosA - SinA
hope it helps!
#JaiHind
zeus6:
dude
any doubt ?
how did CosA/cosA+sinA /cosA became cos^2a/cosA+sinA
it is 1/cosA+sinA no
it is like 6/3/2
6/3*1/2
that is 2*1/2
tanA is written as sinA/CosA
1 not 6/3*2
dude
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Answer:
It is proved by following process
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