Prove that cosA÷1-tanA+sinA÷1-cotA=sinA+cosA
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Step-by-step explanation:
cosA/1-tanA + sinA/1-cotA
=cos²A/cosA-sinA + sin²A/sinA-cosA
=cos²A/cosA-sinA - sin²A/cosA-sinA
=cos²A-sin²A/cosA-sinA
=(cosA-sinA)(cosA+sinA)/cosA-sinA
=cosA+sinA
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