Math, asked by singhashwani778, 1 year ago

Prove that : cosA cos2A cos3A cos8A =sin16A / 16sinA°

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Answered by nishita19

2

There is a mistake in your question
Because cosAcos2Acos4Acos8A=sin16A/16sinA

Answered by grhsvsizxx

0

I cannot understood the ur questions

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