Prove that
(cosA-cosB)²+(sinA-sinB)²=4sin²(A-B/2)
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Answer:
Step-by-step explanation:
1+1-2(CosA.CosB+SinA.SinB)=2-2(Cos(A-B))
=2[1-Cos(A-B)]
=2[1- [1-2Sin²(A-B)/2] ]
=2[ 1-1+2Sin²(A-B)/2]=4Sin²(A-B)/2 =R.H.S
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