prove that cosA+sinA/cosA-sinA=1+tanA/1-tan A
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Login Ask a Question Prove the identities: (sinA - cosA + 1)/(sinA + cosA - 1) = cosA/(1 - sinA) ← Prev QuestionNext Question → 0 votes 19.4k views asked Sep 18, 2018 in Mathematics by AsutoshSahni (52.9k points) Prove the identities: (sinA - cosA + 1)/(sinA + cosA - 1) = cosA/(1 - sinA) trigonometrical identities icse class-10 Share It On 1 Answer 0 votes answered Sep 18, 2018 by AbhishekAnand (87.3k points) selected Sep 19, 2018 by Vikash Kumar (sinA - cosA + 1)/(sinA + cosA - 1) ← Prev QuestionNext Question → Find MCQs & Mock Test Free JEE Main Mock Test Free NEET Mock Test Class 12 Chapterwise MCQ Test Class 11 Chapterwise Practice Test Class 10 Chapterwise MCQ Test Class 9 Chapterwise MCQ Test Class 8 Chapterwise MCQ Test Class 7 Chapterwise MCQ Test Related questions 0 votes 1 answer Prove the identities: √((1 - cosA)/(1 + cosA)) = sinA/(1+cosA) asked Sep 18, 2018 in Mathematics by AsutoshSahni (52.9k points) trigonometrical identities icse class-10 0 votes 1 answer Prove the identities: √((1+sinA)/(1 - sinA)) = cosA/(1 - sinA) asked Sep 18, 2018 in Mathematics by AsutoshSahni (52.9k points) trigonometrical identities icse class-10 0 votes 1 answer Prove the identities: sinA/(1 - cosA) - cotA = cosecA asked Sep 18, 2018 in Mathematics by AsutoshSahni (52.9k points) trigonometrical identities icse class-10 0 votes 1 answer Prove the identities: cosA/(1 + sinA) + tanA = secA asked Sep 18, 2018 in Mathematics by AsutoshSahni (52.9k points) trigonometrical identities icse class-10 0 votes 1 answer Prove the identities: (1 - cosA)/sinA + sinA/(1 - cosA) = 2cisecA asked Sep 18, 2018 in Mathematics by AsutoshSahni (52.9k points) trigonometrical identities icse class-10 Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answel