Question

prove that, (cosA+sinA)/(cosA-sinA) = (1+tanA)/(1-tanA)​

Answer 1

Answer:

( cos A+ sinA )/(cos A- sin A)=( 1+ tanA) /(1- tan

Step-by-step explanation:

L H S cos A ko (cosA + sinA)/(cosA-sinA) in dono sa devide koro ok

now we get cosA+ sinA / cos A and other side cos A - sinA / cosA

cosA / cosA and sinA / cosA we know that cosA divede by cosA is 1and sinA divede by cos A is tanA know we write cosA /cosA ,sinA / cos is 1+ tan A and

cosA - sinA/ cosA

cosA / cosA - sinA / cosA

1 - tanA ara ha to hama chaya tha( 1+ tan A ) (1 - tanA ) = ( 1+ tanA ) ( 1- tanA) hence proved

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Answer 2

Solution:

LHS,

cosA+sinA/cosA-sinA

= cosA/cosA+sinA/cosA/cosA/cosA-sinA/cosA ( ∵Dividing all numerators and denominators by cosA)                                                      

=1+sinA/cosA/1-sinA/cosA

=1+tanA/1-tanA

∴LHS=RHS Proved