prove that
Cose-Sine +1/
Cose + Sine -1
= Cosece+ Cote
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Step-by-step explanation:
devide sine in both numerator & denominator
cote-1+cosece/cote+1-cosece
=cote-1+cosece/cote+1-cosece× cote-cosece/cote-cosece
=cot²e-cosec²e-(cote-cosece)/ (cote-cosece+1)(cote-cosece)
=cot²e-cosec²e-cote+cosece/ (cote-cosece+1)(cote-cosece)
=cot²e-1-cot²e-cote+cosece/ (cote-cosece+1)(cote-cosece)
=-(1+cote-cosece)/ (cote-cosece+1)(cote-cosece)
=-1/-(cosece-cote)
=1/cosece-cote×cosece+cote/cosece+cote
=cosece+cote/cosec²e-cot²e
=cosece+cote [since cosec²e-cot²e=1]
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