Question

prove that (cosec 0 - cot 0) 2=1-cos0 / 1+cos0​

Answer 1

Answer:

class 10

Step-by-step explanation:

its answer in class text book

Answer 2

RHS:

$\frac{1 - \cos0}{1 + \cos0 } \\ \\ now \: multiply \: and \: divide \: with \: 1 - \cos0 \\ \\ = \frac{1 - \cos0}{1 + \cos0} \times \frac{1 - \cos0 }{1 - \cos0 } \\ = \frac{(1 - cos0) {}^{2} }{(1 + \cos0)(1 - \cos0) } \\ = \frac{(1 - \cos0) {}^{2} }{1 - \cos {}^{2} 0} \\ = \frac{(1 - \cos0) {}^{2} }{ \sin {}^{2}0 } \\ ( \frac{1 - \cos0 }{ \sin0} ) {}^{2} \\ = ( \frac{1}{ \sin } - \frac{ \cos0 }{ \sin } ) {}^{2} \\ = ( \csc {}^{2}0 - \cot {}^{2} 0) {}^{2} \: hence \: proved$