Math, asked by saideepakpatil2, 11 months ago

Prove that : cosec^2 (90 - theta) - tan^2 theta/4( cos^2 40 + cis^2 50) - 2tan^2 30*sec^2 52*sin^38/3( cosec^2 70 - tan^2 20) = 1/36

Answers

Answered by jaiswalzais
3

Answer:

This question have many mistakes first correct it and than again send..

ok

Similar questions