Question

Prove that cosec(67+theta)-sec(23-theta)=0

Answer 1

Answer:

cosec(67+¤)-sec(23-¤)

=cosec(67+¤)-sec{90-(67+¤)}

=cosec(67+¤)-cosec(67+¤)=0

Step-by-step explanation:

sec(90-¤)=cosec¤

Answer 2

Hey there!

L.H.S:

cosec (67 + Ф) - sec (23 - Ф)

= sec { 90 - (67 + Ф)} - sec(23 - Ф)

= sec (23 - Ф) - sec (23 - Ф)

= 0

= R.H.S