Question

prove that cosec A/4+cosec A/2+cosec A = cot A/8-cot A​

Answer 1

Answer:

I cannot understand the question

Answer 2

Answer:

cscA(1+cosA)(cscA−cotA)=1

LHS:

sinA

1

[1+cosA][

sinA

1

−

sinA

cosA

][∵cscA=

sinA

1

,cotA=

sin

A

cos

A

]

=

sinA

A

(1+cosA)

sinA

(1−cosA)

=

sin

2

A

1−cos

2

A

[∵ cos

2

A+sin

2

A=1 sin

2

A=1−cos

2

A]

=

sin

2

A

sin

2

A

=1=RHS

Step-by-step explanation:

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