Question

prove that:cosec( a+b)=cosec a cosec b/cot a+cot b

Answer 1

Hi ,

1 ) cotA + cot B

= cosA/ sinA + cosB/sinB

= ( SinBcosA + cosBsinA )/(sinAsinB)

= sin( A+ B ) / sinA sinB

= cosecAcosecB/Cosec( A + B )--( 1 )

Now ,

RHS =( cosecAcosecB)/(cotA+cotB)

=(cosecAcosecB)/[(cosecAcosecB)/Cosec(A+B )]

[ From ( 1 ) ]

= Cosec( A+ B )

= LHS

Hence proved.

I hope this helps you.

: )

Answer 2

Step-by-step explanation:

hope it will help you all