Question

prove that,
Cosec(A+B) = cosecA cosecB/cotA + cotB​

Answer 1

Step-by-step explanation:

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Answer 2

Solution-

RHS=

$\bf \frac{cosecA \:cosecB }{cotA \:+ cotB}$

$= \bf \: \frac{cosecA \: cosecB} {\frac{cosA}{sinA} + \frac{cosB}{sinB} } \\ \\ \bf \frac{cosecA \: cosecB}{ \bf = \frac{(sin \: B \: cosA + cosB \: sinA)}{sinA \: sinB} }\\ \\ \bf = \frac{cosecA \: \: cosecB}{ \frac{sin(A + B)}{sinA \: sinB} }$

°•° 1/sinA = cosecA so,

$= \bf \frac{cosecA \: cosecB}{\frac{cosecA \: cosecB}{cosec(A + B)} } \\ \\ = \bf \: cosec(A + B)$