Prove that: (cosec A-sin A) (sec A- cos A) = 1 /tan A + cot A
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Answer:
LHS=(cosecA−sinA)(secA−cosA)=(sinA1−sinA)(cosA1−cosA)
=(sinA1−sin2A)(cosA1−cos2A)=sinAcosA=21sin2A
RHS=tanA+cotA1=1+tan2AtanA=21sin2A
LHS=RHS
Hence Proved
i hope this is the ans
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