Question

prove that (cosec A-sinA) (sec A-cosA) (tan A+ cot A) = 1.
plz only answer​

Answer 1

Step-by-step explanation:

cosec =$\frac{1}{sin}$, sec =$\frac{1}{cos}$ ($1 -sin^{2}$ =$cos^{2$ ) (1 - $cos^2 = sin^2$) ($sin^2 +cos^2 = 1$)

($\frac{1}{sin}$ - sin) ($\frac{1}{cos}$ - cos)($\frac{sin}{cos}$+$\frac{cos}{sin}$)

($\frac{1-sin^{2} }{cos}$) ($\frac{1-cos^{2} }{sin}$)($\frac{sin^{2}+ cos^{2} }{sincos}$)

($\frac{cos^{2} }{sin}$) ($\frac{sin^{2} }{cos}$)($\frac{1}{sincos}$) = 1

hence proved