Question

prove that cosec (power)4 -cosec2(power) =cot 2+cot4 prove that tan 2 +cot 2

Answer 1

Given Equation is tanA + cotA = 4.

On squaring both sides, we get

= > (tanA + cotA)^2 = (4)^2

= > tan^2A + cot^2A + 2tanAcotA = 16

= > tan^2A + cot^2A + 2 * tanA * (1/tanA) = 16

= > tan^2A + cot^2A + 2 = 16

= > tan^2A + cot^2A = 16 - 2

= > tan^2A + cot^2A = 14.

• On squaring both sides,

we get

= > (tan^2A + cot^2A)^2 = (14)^2

= > tan^4A + cot^4A + 2 * tan^4A * cot^4a = 196

= > tan^4A + cot^4A + 2 * tan^4A * (1/tan^4A) = 196

= > tan^4A + cot^4A + 2 = 196

= > tan^4A + cot^4A = 196 - 2

= > tan^4A + cot^4A

= 194.

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Answer 2

Answer:

Step-by-step explanation:

Given Equation is tanA + cotA = 4.

On squaring both sides, we get

= > (tanA + cotA)^2 = (4)^2

= > tan^2A + cot^2A + 2tanAcotA = 16

= > tan^2A + cot^2A + 2 * tanA * (1/tanA) = 16

= > tan^2A + cot^2A + 2 = 16

= > tan^2A + cot^2A = 16 - 2

= > tan^2A + cot^2A = 14.

On squaring both sides,

we get

= > (tan^2A + cot^2A)^2 = (14)^2

= > tan^4A + cot^4A + 2 * tan^4A * cot^4a = 196

= > tan^4A + cot^4A + 2 * tan^4A * (1/tan^4A) = 196

= > tan^4A + cot^4A + 2 = 196

= > tan^4A + cot^4A = 196 - 2

= > tan^4A + cot^4A

= 194.

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