prove that cosec Sq. theta×cot Sq. theta=sin Sq 22+sin Sq 68.cot Sq 68
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i think so some fault in the question because
LHS
cosec2 theta * cot2 theta
=i/sin2 theta * cos2/sin2
=cos2/sin4
RHS
sin2 22+ sin2 68 * cos2 68/ sin2 68
= sin2 22 + cos2 68
=2sin2 22
LHS
cosec2 theta * cot2 theta
=i/sin2 theta * cos2/sin2
=cos2/sin4
RHS
sin2 22+ sin2 68 * cos2 68/ sin2 68
= sin2 22 + cos2 68
=2sin2 22
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