Question

prove that cosec theta/(cosec theta-1)+cosec theta/(cosec theta +1)=2sec^2theta​

Answer 1

Step-by-step explanation:

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Answer 2

$\frac{cosec \theta}{cosec \theta - 1} + \frac{cosec \theta}{cosec \theta + 1} \\ \\ = cosec \theta( \frac{cosec \theta + 1 + cosec \theta - 1}{ {cosec }^{2} \theta - 1} ) \\ \\ = \frac{2 {cosec}^{2} \theta }{ {cot}^{2} \theta } \\ \\ = 2 {sec}^{2} \theta$