Question

prove that cosec theta minus cot theta whole square equal to 1
minus cos theta by 1 + cos theta

PLEASE ANSWER IT !!!!!!!!
NO

FALSE ANSWER......

Answer 1

Answer:

Step-by-step explanation:

Remember these identities.

csc^2θ = 1/sin^2θ

cotθ = cosθ/sinθ

Proving:

= (cscθ - cotθ)^2

= csc^2θ - 2cscθcotθ + cot^2θ

= 1/sin^2θ - 2(1/sinθ)(cosθ/sinθ) + cos^2θ/sin^2θ

= 1 - 2cosθ + cos^2θ / sin^2θ

= (1 - cosθ)^2 / (1 - cos^2θ)

= (1 - cosθ)^2 / (1 + cosθ)(1 - cosθ)

= (1 - cosθ)/(1 + cosθ) (Verified)

Answer 2

I hope it will help you

Thnx