prove that cosec10-√3sec10=4
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✴Hi,
ℹHere is the answer to your query:-
✅cosec10-root3 sec10=4
✅LHS=1/sin10 - root3/cos10
✅=(cos10-root3 sin10)/sin10.cos10
✅=2(1/2.cos10-root3/2.sin10)/{1/2(2sin10.cos10)}
✅=2 (sin30.cos10-cos30.sin10)/(1/2sin20)
✅=4sin (30-10)/sin20
✅=4sin20/sin20=4=RHS
LHS=RHS
HENCE PROVED
✔THANKS
@SHIVAM
ℹHere is the answer to your query:-
✅cosec10-root3 sec10=4
✅LHS=1/sin10 - root3/cos10
✅=(cos10-root3 sin10)/sin10.cos10
✅=2(1/2.cos10-root3/2.sin10)/{1/2(2sin10.cos10)}
✅=2 (sin30.cos10-cos30.sin10)/(1/2sin20)
✅=4sin (30-10)/sin20
✅=4sin20/sin20=4=RHS
LHS=RHS
HENCE PROVED
✔THANKS
@SHIVAM
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