Question

prove that
cosec2^72-tan2^18=1​

Answer 1

Hey mate

here is your answer

$= {cosec}^{2} 72 - {tan}^{2} 18 \\ = {cosec}^{2} 72 - {cot}^{2} 72 \\ = \frac{1}{ {sin}^{2}72 } - \frac{ {cos}^{2}72 }{ {sin}^{2}72 } \\ = \frac{1 - {cos}^{2}72 }{ {sin}^{2} 72} \\ = \frac{ {sin}^{2}72 }{ {sin}^{2}72 } \\ = 1$

hope it helps you

plzz mark as brainliest answer.

Answer 2

Step-by-step explanation:

we have

cosec^2 72= sec^2 18.

[cosecA= sec(90-A)]

that is

cosec^2 72 - tan^2 18

= sec^2 18- tan^2 18

= 1.

{ identity=

sec^2 A - tan^2 A=1}