Math, asked by ansikaranabhat, 4 months ago

Prove that : cosec20 + cosec40 + cosec80 = cot10 - tan10​

Answers

Answered by Vardhan07
2

Answer:

Hey mate!!

Good morning!!

Step-by-step explanation:

Given,..

cosec 20° + cosec 40° + cosec 80° = cot 10° - tan 10°..

From the R.H.S side..

cot 10° - tan 10 ° = ( cos 10° / sin 10° ) - ( sin 10° / cos 10° )

= ( cos² 10° - sin² 10° ) / ( sin 10° x cos 10° )

= ( cos 10° + sin 10° ) ( cos 10° - sin 10° ) / ( sin 10° x cos 10° )

Hope this helps u..

Have a great day!!

Similar questions