Prove that : cosec20 + cosec40 + cosec80 = cot10 - tan10
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Answer:
Hey mate!!
Good morning!!
Step-by-step explanation:
Given,..
cosec 20° + cosec 40° + cosec 80° = cot 10° - tan 10°..
From the R.H.S side..
cot 10° - tan 10 ° = ( cos 10° / sin 10° ) - ( sin 10° / cos 10° )
= ( cos² 10° - sin² 10° ) / ( sin 10° x cos 10° )
= ( cos 10° + sin 10° ) ( cos 10° - sin 10° ) / ( sin 10° x cos 10° )
Hope this helps u..
Have a great day!!
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