Question

Prove that :-
cosec²A+ cosec²B= cosec²A Cosec² B​

Answer 1

Answer:

Cosec*A Cosec*A

Step-by-step explanation:

Since A and B are complementary angles A+B=90°,

=Cosec*2A+cosec*2B

=Cosec*2A+[Cosec(90°-A)]*2

=Cosec*A+Sec*A

=1/Sin*2A+1/Cos*2A

Cos*2A+Sin*2A/Sin*2A×Cos*2A

=1/Sin*2A.Cos*2A

=Cosec*2A[Sec(90°A-B)]*2

=Cosec*2A.Cosec*2B.

HOPE THIS ANSWER HELPS YOU.......

Answer 2

Answer:

Hi

Step-by-step explanation:

Your ANSWER WAS CORRECT

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