prove that.
cosec²A.tan²A=1/cos ²A
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Answer:
cosec²A.tan²A=1/cos ²A
Step-by-step explanation:
LHS=cosec²A.tan²A
[cosec²A=1/sin²A,
tan²A=sin ²A/cos ²A]
=1/sin²A×sin ²A/cos ²A
=1/cos²A
LHS=RHS
Proved.
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