Math, asked by Anonymous, 9 months ago

prove that [cosecA+cotA]^2=secA+1/secA-1

Answers

Answered by Anonymous

2

Step-by-step explanation:

(CosecA + CotA)²

(1/SinA + CosA/SinA)²

(1 + CosA)²/Sin²A

(1 + CosA)² / (1 - Cos²A)

(1 + CosA)² / (1 + CosA)(1 - CosA)

(1 + CosA)/(1 - CosA)

CosA(1/CosA + 1) / CosA(1/CosA - 1)

= (SecA + 1) / (SecA - 1)

Hence proof

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