prove that cosecA/(cotA+tanA)=cosA
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answer for the given problem is given
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- cotA + tanA = 1/sinAcosA
- cosecA = 1/SinA
⇒ cosecA/(cotA+tanA) = (1/sinA)/(1/sinAcosA)
⇒ cosecA/(cotA+tanA) = sinAcosA/sinA
⇒cosecA/(cotA+tanA) = cosA
Hence Proved !!!
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