prove that (cosecA-sinA) multiplied by (secantA - cos A)= 1/tanA+cotA
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LHS= (cosecA-sin)(secA-cosA)
1/sinA-sinA×1/cosA-cosA
1-sin^2A/sinA×1-cos^2A/cosA
cos^2A/sinA×sin^2A/cosA
cosAsinA
RHS=1/tanA+cotA
1/sinA/cosA+cosA/sinA
1/sin^2A+cos^2A/cosAsinA
cosAsinA
LHS=RHS
hence proved
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