prove that (cosecA-sinA)(secA-cosA)= 1/tanA+cotA
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L.H.S
(cosecA-sinA)(secA-cosA)
=(1/sinA-sinA)(1/cosA-cosA)
=(1-sin^2 A/sinA)(1-cos^2 A/cosA)
=(cos^2 A/ sinA)(sin^2 A/cosA)
= cosA.sinA
R.H.S
1/ tanA+cotA
=1/(sinA/cosA+cosA/sinA)
=1/(sin^A+cos^2A/cosA.sinA)
=1/(1/cosA.sinA)
=cosA.sinA
L.H.S=R.H.S
(PROVED)
hope it will help you ☺️
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