Question

prove that (cosecQ-cotQ)square =1-cosQ/1+cosQ​

Answer 1

$= ( {cosec \alpha - cot \alpha })^{2} \\ = ( { \frac{1 - cos \alpha }{sin \alpha } })^{2} \\ = \frac{ {(1 - cos \alpha })^{2} }{ {sin}^{2} \alpha } \\ = \frac{(1 - cos \alpha ) ^{2} }{1 - {cos}^{2} \alpha } \\ = \frac{( {1 - cos} \alpha ) ^{2} }{(1 - cos \alpha )(1 + cos \alpha )} \\ = \frac{1 - cos \alpha }{1 + cos \alpha }$