Prove that : cossquare0/1-tan0+sincube0/sin0-cos0=1+sin0cos0
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Step-by-step explanation:
cos²O/1-tanO +sin³O/sinO-cosO
=cos³O/cosO-sinO - sin³O/cosO-sinO
=(cos³O-sin³O)/cosO-sinO
=1+sinOcosO
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