Prove that
costheta/1-sintheta+costheta/1+sintheta= 2 sectheta
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costheta+costheta÷(1-sintheta)(1+sintheta)
2costheta÷(1-sinsquaretheta). a square - b square equals (a+b)(a-b)
2costheta ÷ cossquaretheta. 1-sinsquaretheta
So 2 ÷ costheta.
and 1÷costheta equals sectheta
=2sectheta
hence proved
2costheta÷(1-sinsquaretheta). a square - b square equals (a+b)(a-b)
2costheta ÷ cossquaretheta. 1-sinsquaretheta
So 2 ÷ costheta.
and 1÷costheta equals sectheta
=2sectheta
hence proved
leo000:
good method
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take a look at the answer of the answer
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