Math, asked by aduadinan516, 8 months ago

prove that cosx+sinx/cosx-sinx=tan(pai/4+x)​

Answers

Answered by sritarutvik
0

RHS=tan(pai/4+x)=(tanpi + tanx)/(1-tanpi tanx)

=(tan45+tanx)/(1-tan45tanx)

=(1+tanx)/(1-tanx) since tan45=1

=(1+sinx/cosx)/(1-sinx/cosx)

=((cosx+sinx)/cosx) / ((cosx-sinx)/cosx)

=cosx+sinx/cosx-sinx

=LHS

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