prove that cosx+sinx/cosx-sinx=tan(pai/4+x)
Answers
Answered by
0
RHS=tan(pai/4+x)=(tanpi + tanx)/(1-tanpi tanx)
=(tan45+tanx)/(1-tan45tanx)
=(1+tanx)/(1-tanx) since tan45=1
=(1+sinx/cosx)/(1-sinx/cosx)
=((cosx+sinx)/cosx) / ((cosx-sinx)/cosx)
=cosx+sinx/cosx-sinx
=LHS
Similar questions