Question

prove that cosxcos2xcos4xcos8x=sin16x÷16sinx​

Answer 1

Answer:

cosxcos2scos4xcos8x

=1/2sinx[(2sinxcosx)cos2xcos4xcos8x]

=1/2sinx(sin2xcos2xcos4xcos8x)

=1/4sinx[(2sin2xcos2x)cos4xcos8x]

=1/4sinx(sin4xcos4xcos8x)

=1/8sinx[(2sin4xcos4x)cos8x]

=1/8sinx(sin8xcos8x)

=1/16sinx(2sin8xcos8x)

=1/16sinx(sin16x)

=sin16x/16sinx

Step-by-step explanation:

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