Question

prove that: cot /1-sin =sec + tan​

Answer 1

Answer:

L.H.S=secA(1−sinA)(secA+tanA)=(secA−

cosA

sinA

)(secA+tanA)

=(secA−tanA)(secA+tanA)

=sec

2

A−tan

2

A

Putting if tan

2

A+1=sec

2

A−

we get L.H.S=1+tan

2

A−tan

2

A=1

⇒L.H.S=R.H.S