Question

prove that cot 79°-tan 11°=0​

Answer 1

To Prove;

$\cot(79) - \tan(11) = 0$

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Proof

$= > \cot(79) - \tan(11) \\ = > \cot(90 - 11) - \tan(11) \\ = > \tan(11) - \tan(11) \\ = > 0$

Hence Proved

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Formula Used

Tan(90-A)=CotA

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