prove that cot a-cos a /cot A- cos a=cosec a-1 /cosec a+1
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RHS=(cosec A-1)/(cosecA +1)
LHS
=(cotA-cos A )/(cot A+ Cos A)
={(cosA/sin A)-cos A}/{(cos A/sin A+cos A}
=cos A{(1/sin A)-1}/cosA{(1/sin A)+1}
=(cosec A-1)/(cosecA +1)
∴LHS=RHS[∴proved]
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